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If an average jogs, he produces 14.5xx10...

If an average jogs, he produces `14.5xx10^(3)` cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires `580xx10^(3)` cal for evaporation) is

A

0.25 kg

B

2.25 kg

C

0.05 kg

D

0.20 kg

Text Solution

Verified by Experts

The correct Answer is:
A
Amount of sweat evaporated/minute
= `("Sweat produced/minute")/("Number of calories required for evaporation/kg")`
`=("Amount of heat produced per minute in jogging")/("Laten heat (in cal/kg)")` ltBrgt = `(14.5xx10^(3))/(580xx10^(3))=(145)/(580)=0.25` kg
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