`2x^2+4x+7` has minimum value `m` at `x= alpha` then `(alpha,m)=`

the expression 2x ^2 + 4x +7 has minimum value m at x= alpha . The ordered pair ( alpha , m) is

the expression 2x ^2 + 4x +7 has minimum value m at x= alpha . The ordered pair ( alpha , m) is

The minimum value of (x- alpha)(x-beta) is

The minimum value of (x-alpha)(x-beta) is

The minimum value of (x-alpha)(x-beta) is

The minimum values of (x-alpha)(x-beta) is

The minimum value of x^(2)+7x-5 is m at x=lambda then m+lambda =

If the function f(x)=x^(3)+alpha x^(2)+beta x+1 has maximum value at x=0 and minimum value at x=1, then (i)alpha=(2)/(3),beta=0 (ii) alpha=-(3)/(2),beta=0(iii)alpha=0,beta=(3)/(2)(iv) none of these