An unbaised coin is tossed 8 times. Find , by using binomial distribution, the probability of getting at least 6 heads.

Explanation

Solution

p= probability of getting head in one toss=`1/2`

q=`(1-p)`=`frac{1}{2}`

x= no. of heads

therefore `p(x geq 3)`

=`1-p(x leq 2) `

=`1-p(x=0)-p(x=1)-p(x=2)`

Now, `p(x=0)=8^C_0(frac{1}{2})^{0}(frac{1}{2})^{8}`

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