Let ` vec a , vec b , vec c` be three non-zero vectors such that ` vec c` is a unit vector perpendicular to both ` vec aa n d vec b` . If the between ` vec aa n d vec b` is `pi//6` , prove that `[ vec a vec b vec c]^2=1/4| vec a|^2| vec b|^2dot`

Explanation

Solution:

Since,

`vec{c}=lambda(vec{a} times vec{b}) `

`|vec{c}|=1`



Now,

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