The probability that a bulb produced by a factory will fuse after 150 days of use is 0.05. Find the probability that out of 5 such bulbs (i)       none (ii)      not more than one (iii)     more than one (iv)     at least one will fuse after 150 days of use.

Explanation

Solution:

Correct option is A)

Let X represent the number of bulbs that will fuse after 150 days of use in an experiment of 5 trials. The trials are Bernoulli trials.

It is given that, p=`0.05`

`∴q=1−p=1−0.05=0.95`

X has a binomial distribution with n=`5` and p=`0.05`

`∴P(X=x)= n_(C_x)q (n−x)p^x`
, where x=`1,2,...n`

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