A fair die is tossed twice. If the number appearing on the top is less than 3, it is a success. Find the probability distribution of number of successes.

Explanation

Let X denote the event of getting a number less than 3(1or2) on throwing the die.

Then,X can take the values 0,1 and 2


Now,`P(X=0)=16/36​=4/9`
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`P(X=1)=16/36​=4/9`
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`P(X=2)=4/36​=1/9`
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Thus, the probability distribution of X is given by `P(X=0)=4/9​,P(X=1)=4/9​,P(X=2)=1/9`​