Mean and Variance of a binomial variance are 4 and 4/3 respectively then `P(X geq1)` will be

Mean and Variance of a binomial variance are 4 and 4/3 respectively then P(X>=1) will be

Mean and variance of a binomial variate X are 4 and 2 respectively Then P (X =1 )= ……

The mean and standard deviation of a binomial variate X are 4 and 3 respectively. Then, P(Xge1) is equal to

The mean and variance of a binomial distribution are 4 and 4/3 respectively, find P(Xgeq1)dot

If the mean and variance of a binomial variable X are 2 and 1 respectively find P(X>1)

The mean and variance of a binomial distribution are 6 and 4 respectively, then n is