Using vectors: Prove that if a,b,care the lengths of three sides of a triangle then its area `Delta` is given by `Delta= sqrt(s(s-a)(s-b)(s-c))` where 2s=a+b+c

If A is the area and 2s the sum of the sides of a triangle,then

If A is the area and 2s is the sum of the sides of a triangle, then

If a,b,c are the sides of a triangle and s=(a+b+c)/(2), then prove that 8(s-a)(s-b)(s-c)<=abc

Statement I If the sides of a triangle are 13, 14 15 then the radius of in circle =4 Statement II In a DeltaABC, Delta = sqrt(s (s-a) (s-b) (s-c)) where s=(a+b+c)/(2) and r =(Delta)/(s)

Let a<=b<=c be the lengths of the sides of a triangle.If a^(2)+b^(2)

In Delta ABC, a^(2)(s-a)+b^(2)(s-b)+c^(2)(s-c)=

Statement I: The sides of triangle are 20cm,21cm,29cm. Its area is 210cm^(2) Statement II : 2s=(a+b+c), where a,b,c are the sides of triangle,then area=sqrt(s(s-a)(s-b)(s-c))

if A be the area of a triangle,prove that the error in A resulting from small error in the measurement of c is given by dA=(A)/(4)((1)/(s)+(1)/(s-a)+(1)/(s-b)-(1)/(s-c))dc,2s=a+b+c

a,b,c are sides of the triangle and s be its semi perimeter and (s-a)=90, (s-b)=50 and (s-c)=10 then find the area of the triangle