`lim_(x->0)1/x[(1+x)^8-1]=8`

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Show that: lim_(x to 0)(1)/(x)[(1+x)^(8)-1]=8

lim_(x to 0)((1+x)^(8)-1)/((1+x)^(2)-1) is equal to

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lim_(x->8)(x^(1/3)-2)/(x-8)

lim_(x rarr0)((1+x)^((1)/(8))-(1-x)^((1)/(8)))/(x)

lim_(xrarr0) x/((1+sinx)^(1/8)-(1-sinx)^(1/8)) =?

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