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sin[cos^(-1)(3/5)]...

`sin[cos^(-1)(3/5)]`

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Evaluate sin[2cos^(-1)(-3/5)] .

Find the value of sin[2cos^(-1)(-3//5)]

sin{2\ cos^(-1)(-3/5)} is equal to (a) 6//25 (b) 24//25 (c) 4//5 (d) -24//25

sin{2\ cos^(-1)(-3/5)} is equal to 6//25 (b) 24//25 (c) 4//5 (d) -24//25

sin{2cos^(-1)((-3)/(5))}=

sin(2 cos^(-1). 3/5)=

Evaluate: sin [2cos^(-1) ((-3)/(5))]