If costheta>sintheta>0 then I=int \ [ln[...

If `costheta>sintheta>0` then `I=int \ [ln[(1+sin2theta)/(1-sin2theta)]^(cos^2theta)+ln[(cos2theta)/(1+sin2theta)]]`=`Ksin2theta \ ln[(costheta+sintheta)/(costheta-sintheta)]+mln|cos2theta|+c` , then `k+m`=

Similar Questions

Explore conceptually related problems

If costhetagtsinthetagt0 , then evaluate: int{log((1+sin2theta)/(1-sin2theta))^(cos2theta)+log((cos2theta)/(1+sin2theta))}d theta

Evaluate intcos2theta log((costheta+sintheta)/(costheta-sintheta))d theta

int (cos2theta) . log((costheta+sintheta)/(costheta-sintheta))d theta is equal to

Evaluate int{log((1+sin2theta)/(1-sin2theta))^(cos^(2)theta)+log((cos2theta)/(1+sin2theta))}d theta .

If cos theta > sin theta > 0, then evaluate : int{log((1+sin2theta)/(1-sin2theta))^(cos^(2) theta)+log((cos2theta)/(1+sin2theta))} d theta

Solve: costheta+sintheta=cost2theta+sin2theta

(sintheta+sin2theta)/(1+costheta+cos2theta)

(sintheta-2sin^3theta)/(2cos^3theta-costheta) = …………….