Find the equation of a line passing through `(1,-1,0)` and parallel to the line `(x-2)/3=(2y+1)/2=(5-z)/1`

Explanation

Given

` frac{x-2}{3}=frac{2 y+1}{2}=frac{5-z}{-1} `


`Rightarrow frac{x-2}{3}=frac{2(y+1 / 2)}{2}=frac{2-5}{1}`


direction cosines are` (l, m, n)=(3,1,1)`


Equation of line passing
through `(1,-1,0)` is



`frac{x-1}{3}=frac{y+1}{1}=frac{z-0}{1} `


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