The magnetic momentum `Fe^("x+ ")` ion is `sqrt(24)` then the value of `"x"` is

11:x=6:24 ,find the value of x

x>sqrt(24-5x)

The spin only magnetic moment value of Fe^(+2) is

If sqrt(1+(49)/(576))=1+(x)/(24), then the value of x is

Magnetic momentum of an ion M^(+3) is sqrt( 35) BM. Then, number of electron in d orbital of M element will be "___________"