A polynomial P is positive for `x lt 0`, and the area of the region bounded by `P(x)`, then x-axis, and the vertical lines `x=0 and x= K` is `K^(2) (K+3)//3`. The polynomial `P(x)` is

The area of the region bounded by the curve y=2x+3 ,x-axis and the lines x=0 and x=2 is

Find the area of the region bounded by the curve y = x^(2) , the X−axis and the given lines x = 0 , x = 3

The area (in sq. units) of the region bounded by the curves y=2-x^(2) and y=|x| is k, then the value of 3k is

If the area bounded by y=3x^(2)-4x+k , the X-axis and x=1, x=3 is 20 sq. units, then the value of k is

If the quadratic polynomial p(x) is divisible by x - 4 and 2 is a zero of p(x) then find the polynomial p(x).

Let P(x) and Q(x) be two quadratic polynomials such that minimum value of P(x) is equal to twice of maximum value of Q(x) and Q(x)>0AA x in(1,3) and Q(x)<0AA x in(-oo ,1)uu(3, oo) If sum of the roots of the equation P(x) =0 is 8 and P(3)-P(4)=1 and distance between the vertex of y=P(x) and vertex of y=Q(x) is 2sqrt(2) The polynomial P(x) is:

Let P(x) and Q(x) be two quadratic polynomials such that minimum value of P(x) is equal to twice of maximum value of Q(x) and Q(x)>0AA x in(1, 3) and Q (x)<0AA x in(-oo, 1)uu(3, oo) . If sum of the roots of the equation P(x)=0 is 8 and P(3)-P(4)=1 and distance between the vertex of y=P(x) and vertex of y=Q(x) is 2sqrt(2) The polynomial P(x) is:

If 2 and -2 are the zeroes of the polynomial p(x). write the polynomial p(x)

The locus of the point P (h, k), when the area of the triangle formed by the lines y=x, x+y=2 and the line through P (h, k) and parallel to the x - axis is 4h^(2) is