If 2g ice at `0^(0)C` is dropped into `10g` water at `80^(0)C` then temperature of mixture is

540 g of ice at 0^(@)C is mixed with 540 g of water at 80^(@)C . The final temperature of the mixture is

15 g ice at 0^@C is mixed with 10 g water at 40^@C . Find the temperature of mixture. Also, find mass of water and ice in the mixture.

10 g ice at 0^(@)C is mixed with 20 g of water at 20^(@)C . What is the temperature of mixture?

100g ice at 0^(@)C is mixed with 100g water at 100^(@)C . The resultant temperature of the mixture is

A 5 g piece of ice at — 20^° C is put into 10 g of water at 30^° C. The final temperature of mixture is

50 g of ice at 0^@C is mixed with 50 g of water at 80^@C . The final temperature of the mixture is (latent heat of fusion of ice =80 cal //g , s_(w) = 1 cal //g ^@C)

100 g of ice at 0^(@)C is mixed with 100 of water 80^(@)C . The final temperature of the mixture will be

Ice at -20^(@)C is added to 50 g of water at 40 ^(2)C When the temperature of the mixture reaches 0^(@) C it is found that 20 g of ice is still unmelted .The amount of ice added to (Specific heat of water =4.2 j//g//^(@)C Specific heat of Ice =2.1 J//g //^(@)C M Heat of fusion of water of 0^(@)C=334 J//g)