`(sin theta)/(cos3 theta)+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)=lambda[(Tan mu theta)-Tan theta]" then "mu-50 lambda`=

(sin 3theta)/(sin theta)-(cos 3theta)/(cos theta)=

(sin theta)/(cos3 theta)+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)+(sin27 theta)/(cos81 theta)=

Prove that :(sin theta)/(cos(3 theta))+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)=(1)/(2)(tan27 theta-tan theta)

If (sin theta+cos theta)/(sin theta-cos theta)=3 then sin^4 theta-cos^4 theta=

(sin theta+cos theta)(1-sin theta cos theta)=sin^3 theta+cos^3 theta

(sin3 theta+cos3 theta)/(cos theta-sin theta)=1+2xx sin2 theta

Prove that : (sin theta)/(cos[3 theta])+(sin[3 theta])/(cos[9 theta])+(sin[9 theta])/(cos[27 theta])=(1)/(2)[tan[27 theta]-tan[theta]]

3. sin^(3)theta+cos^(3)theta=(sin theta+cos theta)(1-sin theta cos theta)

(sin theta)/(cos(3theta))+(sin(3theta))/(cos(9theta))+(sin(9theta))/(cos(27theta))+(sin(27theta))/(cos(81theta))=

(sin theta+sin3 theta+sin5 theta)/(cos theta+cos3 theta+cos5 theta)=tan3 theta