One extremity of a focal chord of `y^2 = 16x` is `A(1,4)`. Then the length of the focal chord at A is

The point (1,2) is one extremity of focal chord of parabola y^(2)=4x .The length of this focal chord is

If the point ( at^2,2at ) be the extremity of a focal chord of parabola y^2=4ax then show that the length of the focal chord is a(t+t/1)^2 .

If the point (at^(2),2at) be the extremity of a focal chord of parabola y^(2)=4ax then show that the length of the focal chord is a(t+(1)/(t))^(2)

If the lsope of the focal chord of y^(2)=16x is 2, then the length of the chord, is

If the area of the triangle inscribed in the parabola y^(2)=4ax with one vertex at the vertex of the parabola and other two vertices at the extremities of a focal chord is 5a^(2)//2 , then the length of the focal chord is

If t is the parameter of one end of a focal chord of the parabola y^(2) = 4ax , show that the length of this focal chord is (t + (1)/(t))^(2) .

If (t^(2),2t) is one end ofa focal chord of the parabola,y^(2)=4x then the length of the focal chord will be:

the distance of a focal chord of the parabola y^(2)=16x from its vertex is 4 and the length of focal chord is k ,then the value of 4/k is