" The hydrogen ion concentration of "0.2M" of \(CH_{3}\)COOH" Which is "4%" ionized is "

The hydrogen ion concentration of 0.001 M NaOH solution is

[H^(+)] of 0.02 NCH_(3) COOH which is 4% dissociated, is

The pH of a 0.1 M CH_(3)COOH which is 2% ionised in aqueous solution is

The H^(+) ion concentration in 0.001 M CH_(3)CO_(2)H (K_(a) = 1.8 xx10^(-5)) is 1.34 xx10^(-4) g ion /L . The H^(+) ion concentration if 0.164 g of CH_(3)CO_(2)Na is added to one litre of 0.001 M CH_(3)CO_(2)H will be

Calculate the H^+ ion concentration in 0.1 M CH_3COOH if the degree of dissociation of the acid is 0.0132