In a town of 10000 families, it was found that 40% families buy newspaper A, 20% families buy newspaper B, 10 % families buy newspaper C, 5% families buy A and B, 3% buy B and C and 4 % buy a and C. If 2% families buy all the three newspaper. Find
(i) the number of familiar which buy newspaper A only.
(ii) the number of familiar which buy none of A , B and C.

Explanation

To solve the problem step by step, we will first define the variables and then calculate the required values.

### Given Data:
- Total families = 10,000
- Families buying Newspaper A (N(A)) = 40% of 10,000 = 4,000
- Families buying Newspaper B (N(B)) = 20% of 10,000 = 2,000
- Families buying Newspaper C (N(C)) = 10% of 10,000 = 1,000
- Families buying both A and B (N(A ∩ B)) = 5% of 10,000 = 500
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