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y = f(x) = (ax-b)/(cx-a) then f(y) = ?...

`y = f(x) = (ax-b)/(cx-a)` then f(y) = ?

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We have,`f(x)=y=(ax-b)/(cx-a)`
`:. f(y) =(ay-b)/(cy-a)=(a((ax-b)/(cx-a))-b)/(c((ax-b)/(cx-a))-a)`
`=(a(ax-b)-b(cx-a))/(c(ax-b)-a(cx-a))=(a^(2)x-ab-bcx+ab)/(acx-bc-acx+a^(2))`
`=(a^(2)x-bcx)/(a^(2)-bc)=(x(a^(2)-bc))/((a^(2)-bc))=x`
`:. f(y) =x`
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