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If P={1,2} then PxxPxxP={(1,1,1,),(2,2,2...

If `P={1,2}` then `PxxPxxP={(1,1,1,),(2,2,2),(1,2,2,),(2,1,1)}`

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To solve the problem, we need to determine whether the given set \( P \times P \times P = \{(1,1,1), (2,2,2), (1,2,2), (2,1,1)\} \) is correct or not. ### Step-by-step Solution: 1. **Identify the Set \( P \)**: - We are given \( P = \{1, 2\} \). 2. **Calculate \( P \times P \)**: - The Cartesian product \( P \times P \) consists of all ordered pairs formed by taking one element from \( P \) and pairing it with every element in \( P \). - Therefore, \( P \times P = \{(1,1), (1,2), (2,1), (2,2)\} \). 3. **Calculate \( P \times P \times P \)**: - Now, we need to compute \( P \times P \times P \), which is the Cartesian product of \( P \times P \) with \( P \). - This means we will take each element from \( P \times P \) and pair it with every element in \( P \): - From \( (1,1) \): \( (1,1,1), (1,1,2) \) - From \( (1,2) \): \( (1,2,1), (1,2,2) \) - From \( (2,1) \): \( (2,1,1), (2,1,2) \) - From \( (2,2) \): \( (2,2,1), (2,2,2) \) 4. **List All Elements of \( P \times P \times P \)**: - Combining all these, we get: - \( (1,1,1) \) - \( (1,1,2) \) - \( (1,2,1) \) - \( (1,2,2) \) - \( (2,1,1) \) - \( (2,1,2) \) - \( (2,2,1) \) - \( (2,2,2) \) 5. **Count the Total Elements**: - There are a total of 8 elements in \( P \times P \times P \). 6. **Compare with the Given Set**: - The provided set \( \{(1,1,1), (2,2,2), (1,2,2), (2,1,1)\} \) contains only 4 elements. - Since \( P \times P \times P \) should have 8 elements, the statement is false. ### Conclusion: The statement that \( P \times P \times P = \{(1,1,1), (2,2,2), (1,2,2), (2,1,1)\} \) is **false**.

To solve the problem, we need to determine whether the given set \( P \times P \times P = \{(1,1,1), (2,2,2), (1,2,2), (2,1,1)\} \) is correct or not. ### Step-by-step Solution: 1. **Identify the Set \( P \)**: - We are given \( P = \{1, 2\} \). 2. **Calculate \( P \times P \)**: ...
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