A man saved Rs. 66000 in 20 years. In each succeeding year after the
first year he saved Rs. 200 more than what he saved in the previous year. How
much did he save in the first year?
Text Solution
Verified by Experts
Let saved in first Rs. Since each succeeding year an ncrement Rs. 200 has made. So , it forms an AP whose Fiist term = a common difference (d) - 200 and b-20yr `thererfore S_(20)=(20)/(2)[2a+(20-1)d] [:' S_(n)=(n)/(2){2a+(n-1)d}]` `implies 660000=10[2a+19d]` `implies 66000=20a+190d` `implies 66000=20a+190xx200` `implies 20a=66000-38000` `implies 20a=28000` `therefore a=(28000)/(20)=1400` hence , he saved Rs. 1400 in the first year.
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