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The probability that atleast one of the events A and B occurs is 0.6 If A and B occur simulataneously with probability 0.2, then `Poverset(-)((A))+Poverset(-)((B))` is equal to

A

`0.4`

B

`0.8`

C

`1.2`

D

`1.6`

Text Solution

Verified by Experts

The correct Answer is:
C
(c) `"Given, "P(AcupB)=0.6 and P(AcapB)=0.2`
`therefore" "P(AcupB)=P(A)+P(B)-P(AcapB)`
`rArr" "0.6=P(A)+P(B)-0.2`
`rArr" "P(A)+P(B)=0.8`
`therefore" "Poverset(-)((A))+Poverset(-)((B))=1-P(A)+1-P(B)`
`=2-[P(A)+P(B)]`
`=2-0.8=1.2`
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