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The probability of happening of an event A is 0.5 and that of B is 0.3. If A and B are mutually exclusive events, then the probability of neither A nor B is…..

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`P(overset(-)(A)capoverset(-)(B))=P(bar(AcupB))=1-P(AcupB)`
`=1-[P(A)+P(B)]" "["since, A and B are mutually exclusive"]`
`=1-(0.5+0.3)=1-0.8=0.2`
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