Home
Class 9
MATHS
Simplify the following (i) sqrt45-3sqrt...

Simplify the following (i) `sqrt45-3sqrt20+4sqrt5` (ii) `sqrt(24)/8 + sqrt54/9` (iii) `root4(12) xx root7(6)` (iv) `4sqrt28 div 3sqrt7 div root3(7)` (v)` 3sqrt3+2sqrt27 + 7/(sqrt3)` (vi) `(sqrt3-sqrt2)^(2)` (vii) `root4(81)-8root3(216)+15root5(32)+ sqrt225` (viii) `3/sqrt8+ 1 / sqrt2` (ix) `(2sqrt3)/3- (sqrt3)/6`

Text Solution

Verified by Experts

`sqrt45-3sqrt20+4sqrt5= sqrt(3xx3xx5)-3sqrt(2xx2xx2)+4sqrt5`
` 3sqrt5-3xx2sqrt5+4sqrt5`
`3sqrt5-6sqrt5+4sqrt5=sqrt5`
`sqrt24/8+sqrt54/9=sqrt(2xx2xx2xx2xx3)/8+sqrt(3xx3xx3xx2)/9`
`(2sqrt6)/8 + (3sqrt6)/9=sqrt6/4+sqrt6/3`
`(3sqrt6+4sqrt6)/12=(7sqrt6)/12`
`root4(12)xxroot7(6)=(12)^(1//4)xx(6)^(1//7)`
`(2xx2xx3)^(1//4)xx(2xx3)^(1//7)=2^(1//4).2^(1//4).3^(1//4).2^(1//7).3^(1//7)`
`2^(1/4+1/4+1/7)xx3^(1/4+1/7)` `2^(9//14)xx3^(11//28)=root14(2^(9))root28(3^(11)) " " [ x^(m).x^(n)=x^(m+n)]`
`root28(2^(18))root28(33^(11))=root28(2^(18)xx3^(11)) " " [ root na= root(mn)(a^(m))`
(iv) `4sqrt28+3sqrt7 div root3(7) =(4sqrt(4xx7)div3sqrt7)divroot3(7)`
` ((8sqrt7)/(3sqrt7))div(7)^(1/3)`
`8/3div7^(1/3)= 8/(3root3(7))`
(v) `3sqrt3+2sqrt27+7/sqrt3=3sqrt3+2sqrt(3xx3xx3)+7/sqrt3xxsqrt3/sqrt3`
`3sqrt3+ 6sqrt3+(7sqrt3)/3=9sqrt3+(7sqrt3)/3`
`3sqrt3+6sqrt3+(7sqrt3)/3=9sqrt3+(7sqrt3)/3`
`(27sqrt3+7sqrt3)/3=(34sqrt3)/3`
(vi) `(sqrt3-sqrt2)^(2)+(sqrt2)^(2)-2sqrt3xxsqrt2 ` [ using identity , `(a-b)^(2)= a^(2+b^(2)-2ab]`
`3+2-2sqrt(3xx2)=5-2sqrt6`
(vii) `root4(81)-8root3(216)+15root5(32)+sqrt225`
`(81)^(1/4)-8xx(6^(3))^(1/3)15xx(32)^(1/5)+sqrt((15)^(2))`
` (3^(4))^(1/4)-8xx(6^(3))^(1/3)+15xx2^(5xx(1/5))+15`
`3^(1)-8xx6^(1)+15xx2^(1)+15`
3-48+30+15
48-48=0
`3/sqrt8+1/sqrt2=3/(sqrt(2xx2xx2))+1/sqrt2=3/(2sqrt2)+1/sqrt2`
` (3+2)/(2sqrt2)+1/sqrt2`
`(5sqrt2)/(2xx2)=5/(2sqrt2)xxsqrt2/sqrt2`
`(5sqrt2)/(2xx2)=(5sqrt2)/4`
(ix) `(2sqrt3)/3-sqrt3/6=(4sqrt3-sqrt3)/6=(3sqrt3)/6=sqrt3/2`
Promotional Banner

Topper's Solved these Questions

  • NUMBER SYSTEMS

    NCERT EXEMPLAR|Exercise SHORT ANSWER TYPE QUESTIONS|1 Videos
  • LINES AND ANGLES

    NCERT EXEMPLAR|Exercise Lines And Angles|34 Videos
  • POLYNOMIALS

    NCERT EXEMPLAR|Exercise Polynomials|72 Videos

Similar Questions

Explore conceptually related problems

The square root of ( (sqrt3 + sqrt2)/(sqrt3 - sqrt2)) is

(i) 3sqrt(5) by 2sqrt(5) ,(ii) 6sqrt(15) by 4sqrt(3) , (iii) 2sqrt(6) by 3sqrt(3) (iv) 3sqrt(8) by 3sqrt(2) ,(v) sqrt(10) by sqrt(40) , (vi) 3sqrt(28) by 2sqrt(7)

sqrt(7+4sqrt3) - sqrt(7-4sqrt3) =

Simplify: (i) (2 sqrt(2) + 3 sqrt(3)) (2 sqrt(2) - 3 sqrt(3)) (ii) (2 sqrt(8) - 3 sqrt(2))^(2) (iii) (sqrt(7) + sqrt(6))^(2) (iv) (6 - sqrt(2))(2 + sqrt(3))

Simplify the following expressions: (4+sqrt(7))(3+sqrt(2))( (ii) (3+sqrt(3))(5-sqrt(2))(sqrt(5)-2)(sqrt(3)-sqrt(5))

The square root of (7+3sqrt5) (7-3sqrt5) is (A) 4 (B) sqrt5 (C) 3sqrt5 (D) 2

Rationalise the denominator of the following (i) 2/(3sqrt3) , (ii) sqrt40/sqrt3 ,(iii) (3+sqrt2)/(4sqrt2) (iv) 16/(sqrt41-5) ,(v) (2+sqrt3)/(2-sqrt3) , (vi) sqrt6/(sqrt2+sqrt3) (vii) (sqrt3+sqrt2)/(sqrt3-sqrt2) ,(viii) (3sqrt5+sqrt3)/(sqrt5-sqrt3) , (ix) (4sqrt3+5sqrt2)/(sqrt48+sqrt18)