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In the figure, BA|""| ED and BC|""| EF. ...

In the figure, BA`|""|` ED and BC`|""|` EF. Show that `/_`ABC = `/_`DEF.

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Given BA`||`Ed and BC `||` EF
To show `/_`ABC = `/_`DEF
Contstruction Draw ray EP opposite to ray ED.

Proof In the figure , BA`||`ED or BA `||`DP `:." " /_ABP = /_EPC " "` [corresponding angles]
`rArr " " /_ABC = /_EPC " "`....(i)
Again, `" "` BC`||` EF or PC `||` EF
`:. " " /_DEF = /_EPC " " `[corresponding angles] ...(ii)
From Eqs. (i) and (ii) ,
`/_ABC = /_`DEF
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