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Prove that through a given point, we ca...

Prove that through a given point, we can draw only one perpendicular to a given line.

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To prove that through a given point, we can draw only one perpendicular to a given line, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Elements**: - Let line \( L \) be the given line. - Let point \( P \) be the given point from which we want to draw a perpendicular to line \( L \). ...
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NCERT EXEMPLAR-LINES AND ANGLES -Lines And Angles
  1. Two adjacent angles are equal. Is it necessary that each of these angl...

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  2. If one of the angles by two intersecting lines is a right angles, what...

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  3. In the figure, which of the two lines are parallel and why ?

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  4. Two lines l and m , are perpendicular to the same line n. Are l and m...

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  5. In the figure, OD is the bisector of /AOC, OE is the bisector of /BOC ...

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  6. In the figure, /1 =60^(@) and /6 =120^(@) Show that the lines m and n ...

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  7. AP and BQ are the bisectors of the two alternate interior angles forme...

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  8. In the given figure, bisectors AP and BQ of the alternate interior ang...

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  9. In the figure, BA|""| ED and BC|""| EF. Show that /ABC = /DEF.

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  10. In the figure, BA || ED and BC || EF. Show /ABC + /DEF = 180^(@).

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  11. In the figure, DE|""| QR and BP are bisectors of /EAB and /RBA, respec...

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  12. A Delta ABC is right angled at A. L is a point on BC such that ALbot B...

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  13. Two lines are respectively perpendicular to two parallel lines. Show ...

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  14. If two lines intersect prove that the vertically opposite angles are ...

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  15. Bisectors of interior /B and exterior /ACD of a DeltaABC intersect at ...

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  16. A transversal intersects two parallel lines. Prove that the bisectors ...

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  17. Prove that through a given point, we can draw only one perpendicular ...

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  18. Prove that two lines that are respectively perpendicular to two inters...

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  19. prove that triangle must have atleast two acute angle

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  20. In Figure P S\ is the bisector of /Q P R\ a n d\ P T\ |Q R . Show tha...

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