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Diagonals of a quadrilateral ABCD bisect...

Diagonals of a quadrilateral ABCD bisect each other. If `angleA=35^(@), ` determine `angleB`.

A

`angleB=145^(@)`

B

`angleB=115^(@)`

C

`angleB=135^(@)`

D

`angleB=125^(@)`

Text Solution

Verified by Experts

The correct Answer is:
A

Since, diagonals of a quadrilateral bisect each other, so it is a parallelogram.
Therefore, the sum of interior angles between two parallel lines is `180^(@)` i.e.,
`angleA+angleB=180^(@)`
`rArr" "angleB=180^(@)-angleA=180^(@)-35^(@)" "[angleA=35^(@),"given"]`
`rArr" "angleB= 145^(@)`
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