If the radius of a right circular cone is halved and height is doubled then what will be new volume?

Explanation

False
Let the radius of a right circular cone be r and height of a right circule cone be h.
Then, the volume of a right cicrular cone `=(1)/(3) pir^(2)h`
Now, `r = (r)/(2), h = 2h`
New volume of a right cicrular cone `= (1)/(3) pi ((r^(2))/(2)) xx (2h) = (1)/(3)pi xx (r^(3))/(4) xx 2h`
`= (1)/(3) pi xx (r^(2))/(2)h = (1)/(2) ((1)/(3)pir^(2)p)`
Hence, the new volume of a right cicrular cone becomes half of original volume of a right circular cone.