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If m is the mid-point and l is the upper...

If m is the mid-point and l is the upper limit of a class in a continous frequency distribution, then lower class limit of the class is

A

`2m + l`

B

`2m-l`

C

`m-l`

D

`m-2l`

Text Solution

Verified by Experts

The correct Answer is:
B
Let x and y be the lower and upper class limit of a continuous frequency distribution.
Now, mid-point of a class =`(x+y)/2=m` (given)
`rArr x+y=2m rArr x+l=2m` [`therefore` y=l=upper class limit (given)]
`rArr x=2m-l`
Hence, the lower class limit of the class is 2m-l.
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