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If barx(1), barx(2), barx(3),………barx(n) ...

If `barx_(1), barx_(2), barx_(3),………barx_(n)` are the means of n groups with `n_(1), n_(2), …………,n_(n)` number of observations, respectively, then the mean `barx` of all the groups taken together is given by

A

`underset(i=1)overset(n)Sigman_(i)barx_(i)`

B

`(underset(i=1)overset(n)Sigman_(i)barx_(i))/(n^(2))`

C

`(underset(i=1)overset(n)Sigman_(i)barx_(i))/(underset(i=1)overset(n)Sigman_(i))`

D

`(underset(i=1)overset(n)Sigman_(i)barx_(i))/(2n)``

Text Solution

Verified by Experts

The correct Answer is:
C
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