Following table gives the distribution of students of sections A and B of a class according to the marks obtained by them.

Represent the marks of the students of both the sections on the same graph by two frequency polygons. What do you observe?

Explanation

Firstly, we find the mid marks of the given sections A and B by using the formula
Class mark `=("Lower limit + Upper limit")/(2)`
So, the new table for section A and section B is shown below.

We can draw a frequency polygon by plotting the class marks along the horizontal axis and the frequency along the vertical axis.
Now, plotting all the points A(7,5,5), B(22.5,12), C(37.5,28), D(52.5, 30), E(67.5, 35), F(82.5, 13) for section A.
Also, plotting all the pints H(7.5,3), I(22.5,16), J(37.5,25), K(52.5,27), L(67.5, 40) and M(82.5, 10) for section B.

It is clear from the graph that maximum marks 67.5 score by 40 students in section B.