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Four bad oranges are mixed accidently with 16 good oranges. Find the probability distribution of the number of bad oranges in a draw of two oranges.

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To find the probability distribution of the number of bad oranges in a draw of two oranges from a mixture of 4 bad oranges and 16 good oranges, we will denote the random variable \( X \) as the number of bad oranges drawn. The possible values of \( X \) are 0, 1, and 2. ### Step-by-Step Solution: 1. **Identify Total Oranges**: - Total number of oranges = Number of good oranges + Number of bad oranges - Total = 16 good + 4 bad = 20 oranges. ...
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RD SHARMA-MEAN AND VARIANCE OF A RANDOM VARIABLE -Solved Examples And Exercises
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  2. An unbiased die is thrown twice. Find the probability distribution of ...

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  3. Four bad oranges are mixed accidently with 16 good oranges. Find the ...

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  14. In a game 3 coins are tossed. A person is paid Rs. 5, if he gets all h...

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  16. Two cards are drawn without replacement from a well-shuffled deck of 5...

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  17. Find the probability distribution of the number of green balls drawn ...

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  18. From a lot of 10 items containing 3 defectives, a sample of 4 items id...

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