If `|z|=1` and `w=(z-1)/(z+1)` (where `z!=-1),` then `R e(w)` is 0 (b) `1/(|z+1|^2)` `|1/(z+1)|,1/(|z+1|^2)` (d) `(sqrt(2))/(|z|1""|^2)`

If |z|=1 and w=(z-1)/(z+1) (where z!=-1), then Re(w) is 0(b)(1)/(|z+1|^(2))|(1)/(z+1)|,(1)/(|z+1|^(2))(d)(sqrt(2))/(|z|1|^(2))

If |z|=1 and w=(z-1)/(z+1) (where z ne -1 ), then Re (w) is :

If |z|=1 and w=(z-1)/(z+1) (where z!=-1) then Re(w) is (A) 0(B)-(1)/(|z+1|^(2))(C)|(z)/(z+1)|(1)/(|z+1|^(2))(D)(sqrt(2))/(|z+1|^(2))

If |z|=1 and omega=(z-1)/(z+1) (where z in -1 ), then Re (omega) is

If abs(z)= 1 and omega = frac{z-1}{z+1} (where z != -1 ), the Re(omega) is

If |z|=1 and |omega-1|=1 where z, omega in C ,then the range of values of |2z-1|^(2)+|2 omega-1|^(2) equals

If z_(1) and z_(2) are two complex numbers,then (A) 2(|z|^(2)+|z_(2)|^(2)) = |z_(1)+z_(2)|^(2)+|z_(1)-z_(2)|^(2) (B) |z_(1)+sqrt(z_(1)^(2)-z_(2)^(2))|+|z_(1)-sqrt(z_(1)^(2)-z_(2)^(2))| = |z_(1)+z_(2)|+|z_(1)-z_(2)| (C) |(z_(1)+z_(2))/(2)+sqrt(z_(1)z_(2))|+|(z_(1)+z_(2))/(2)-sqrt(z_(1)z_(2))|=|z_(1)|+|z_(2)| (D) |z_(1)+z_(2)|^(2)-|z_(1)-z_(2)|^(2) = 2(z_(1)bar(z)_(2)+bar(z)_(1)z_(2))

If |z|=1 and let omega=((1-z)^2)/(1-z^2) , then prove that the locus of omega is equivalent to |z-2|=|z+2|

If |z|=1 and let omega=((1-z)^2)/(1-z^2) , then prove that the locus of omega is equivalent to |z-2|=|z+2|

If |z|=1 and let omega=((1-z)^2)/(1-z^2) , then prove that the locus of omega is equivalent to |z-2|=|z+2|