If `sin(alpha+beta)=1,sin(alpha-beta)=1/2` where `alpha,beta in[0,pi/2],` then `tan(alpha+2beta)tan(2alpha+beta)` is equal to

If sin(alpha+beta)=1,sin(alpha-beta)=(1)/(2) where alpha,beta in[0,(pi)/(2)], then tan(alpha+2 beta)tan(2 alpha+beta) is equal to

If sin(alpha+beta)=1 and sin(alpha-beta)=1/2 where alpha,beta in [0,pi/2] , then tan(2alpha+beta)=

If sin(alpha + beta) = 1 , sin(alpha - beta) = 1/2 , then : tan(alpha + 2beta)tan(2alpha + beta) is equal to :

If sin (alpha+beta)=1, sin (alpha-beta)=1/2 , then tan (alpha+ 2beta). tan (2 alpha+beta) is equal to :

If sin(alpha+beta)=1 and sin(alpha-beta)=1/2 , where 0lt=alpha, betalt= pi/2 , then find the values of tan(alpha+2beta) and tan(2alpha+beta) .

sin(alpha+beta)=1 and sin(alpha-beta)=(1)/(2)quad 0<=alpha,beta,<=(pi)/(2), then find tan(alpha+2 beta) and tan(2 alpha+beta)

csc^(2)(alpha+beta)-sin^(2)(beta-alpha)+sin^(2)(2 alpha-beta)=cos^(2)(alpha-beta) where alpha,beta in(0,(pi)/(2)), then sin(alpha-beta) is equals

If sin (alpha + beta)=1, sin (alpha- beta)= (1)/(2) , then tan (alpha + 2beta) tan (2alpha + beta) =