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" Tew times "L(2):x=5,y/(3-a)=z/-2" and ...

" Tew times "L_(2):x=5,y/(3-a)=z/-2" and "L_(y)x=6,y/*1-z/(2-a)" are coplanar.Then a can "

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Two lines L_1: x=5, y/(3-alpha)=z/(-2) and L_2: x=alpha, y/(-1)=z/(2-alpha) are coplanar. Then alpha can take value (s) a. 1 b. 5 c. 3 d. 4

Two lines L_1: x=5, y/(3-alpha)=z/(-2) and L_2: x=alpha, y/(-1)=z/(2-alpha) are coplanar. Then alpha can take value (s) a. 1 b. 2 c. 3 d. 4

Two lines L_1: x=5, y/(3-alpha)=z/(-2) and L_2: x=alpha, y/(-1)=z/(2-alpha) are coplanar. Then alpha can take value (s) a. 1 b. 2 c. 3 d. 4

Two lines L_1: x=5, y/(3-alpha)=z/(-2) and L_2: x=alpha, y/(-1)=z/(2-alpha) are coplanar. Then alpha can take value (s) a. 1 b. 2 c. 3 d. 4

Two lines L_(1):x=5,(y)/(3-alpha)=(z)/(-2) and L_(2):x=alpha,(y)/(-1)=(z)/(2-alpha) are coplanar.Then alpha can take value (s) a.1 b.2 c.3 d.4

Two lines L_(1) : x=5, (y)/(3-alpha)=(z)/(-2) and L_(2) : x=alpha, (y)/(-1)=(z)/(2-alpha) are coplanar. Then, alpha can take value(s)

Two lines L_(1) : x=5, (y)/(3-alpha)=(z)/(-2) and L_(2) : x=alpha, (y)/(-1)=(z)/(2-alpha) are coplanar. Then, alpha can take value(s)

Two lines L_(1) : x=5, (y)/(3-alpha)=(z)/(-2) and L_(2) : x=alpha, (y)/(-1)=(z)/(2-alpha) are coplanar. Then, alpha can take value(s)

Two lines L_(1) : x=5, (y)/(3-alpha)=(z)/(-2) and L_(2) : x=alpha, (y)/(-1)=(z)/(2-alpha) are coplanar. Then, alpha can take value(s)