" Frutbuye "=8(x+y)^(3)-2y(x-y)^(3)

3-8 (2x-y) +4 (2x-y) ^ (2)

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))

(x+y)/(2)-(x-y)/(3)=8,(x+y)/(3)+(x-y)/(4)=4

If (2x)/(3y)+(3y)/(2x)=1,(x,y!=0), then the value of 8x^(3)+27y^(3) is

If (x^(2) + y^(2))/(x^(2) - y^(2)) = 2(1)/(8) , find : (i) (x)/(y) (ii) (x^(3) + y^(3))/(x^(3) - y^(3))

If x-2y+2z=0, then x^(3)-8y^(3)+8z^(3) is equal to

Solve for x and y (3x-y)/(5)=2y-1, (3x)/(8)-(y)/(4)=(1)/(2)

The value of (x-y)^3+(x+y)^3+3(x-y)^2(x+y)+3(x+y)^2(x-y) is