If AA + BB + CC = ABC, then Find A, B and C

Let a,b,c,d,A,B,C,D in R . If A/a = B/b = C/c = D/d then (sqrt(Aa) + sqrt(Bb) + sqrt(Cc) + sqrt(Dd)) / (sqrt(a+b+c+d) sqrt(A+B+C+D))=

If A/a = B/b = C/c= D/d then prove that sqrt(Aa)+sqrt(Bb)+sqrt(Cc)+sqrt(Dd)= sqrt((a+b+c+d)(A+B+C+D))

ABC is a right angled triangle, B being the right angle. Mid-points of BC and AC are respectively B' and A'. The ratio of the area of the quadrilateral AA' B'B to the area of the triangles ABC is

In a polygenic cross Aa Bb Cc xx Aa Bb Cc, the phenotypic ratio of offspring is 1:6:'X':20:X:6:1 . What is the value of 'X'

The medians AA' and BB' of triangle ABC intersect at right angle, If BC=3, AC =4, then AB is

If the determinant |b-cc-a a-bb^(prime)-c ' c^(prime)-a ' a^(prime)-b ' b^-c ' ' c^-a ' ' a^-b ' '|=m|a b c a ' b ' c ' a ' ' b ' ' c ' '| , then the value of m s 0 b. 2 c. 1 d. -1

Some genomic representation of skin colour are given below (i) AA bb CC (ii) AA bb cc (iii) AA BB CC (iv) aa bb cc Which of the optin is correct for showing the darkness of colour of the skin in decreasing order