Evaluate: `int1/(x^3sqrt(x^2-a^2))dx`

Explanation

`I=int1/(x^3sqrt(x^2-a^2))dx`


let `x=asec theta`


`dx=asec theta tan theta d theta`


`I=int(asec theta tan theta d theta)/((a^3 sec^3 theta)sqrt(a^2sec^2 theta-a^2`


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