" (b) "sin{log(1+x^(2))}

lim_(x to 0) (A "sin" x + B log (1 + x^(2)) + C (1 - cos x))/(x^(2)) = 2 then Statement-1 : A = 1 Statement-2 : 2B + C = 4 Statement-3 A + B + C = 0

lim_(x to 0) (A "sin" x + B log (1 + x^(2)) + C (1 - cos x))/(x^(2)) = 2 then Statement-1 : A = 1 Statement-2 : 2B + C = 4 Statement-3 A + B + C = 0

If f '(x) = sin (log x) and y = f ((2x + 3)/(3 - 2x )), then (dy)/(dx) at x =1 is equal to : a) 6 sin log (5) b) 5 sin log (6) c) 12 sin log (5) d) 5 sin log (12)

If a=lim_(x rarr oo)(sin x)/(x)&b=lim_(x rarr0)(sin x)/(x) Then int_(a)^(b)(log(1+x))/(1+x^(2))dx is equal to

If a=lim_(x rarr oo)(sin x)/(x)&b=lim_(x rarr0)(sin x)/(x) Then int_(a)^(b)(log(1+x))/(1+x^(2))dx is equal to

log (sin ^(-1)x)

log (sin ^(-1)x)

The value of underset( x rarr 0 ) ( "Lim") ( sin ( ln ( 1+ x)))/( ln ( 1+ sin x )) is

If y = a cos (log x) -b sin (log x), thenx ^ (2) y_ (2) + xy_ (1) + y =

If "log"_(2) "sin" x - "log"_(2) "cos" x - "log"_(2) (1-"tan"^(2) x) =-1 , then x =