[(3)/(x)-(1)/(y)=-9],[(2)/(x)+(3)/(y)=5]

Solve the following system of equations: (3)/(x)-(1)/(y)=-9,quad (2)/(x)+(3)/(y)=5

Solve for x,y(5)/(x)+(3)/(y)=30 and (9)/(x)-(5)/(y)=2

(3) / (x) - (1) / (y) + 9 = 0 (2) / (x) + (3) / (y) = 5, (! = 0, y! = 0)

( 3 ) /(x) - (1 ) /( y) + 9 = 0 , (2)/(x) + ( 3)/( y) = 5 ( x ne 0 , y ne 0 )

(x+1)/(2)+(y+1)/(3)=9,(x-1)/(3)+(y+1)/(2)=8 then x=………

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

Solve by cross-multiplication method (2)/( x) + ( 3)/( y ) = 5, ( 3)/( x ) - (1)/( y ) + 9 = 0

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))