(2sec theta+3tan theta+5sin theta-7cos theta+5)/(2tan theta+3sec theta+5cos theta+7sin theta+8)

(2sec theta+3 tan theta+5 sin theta -7cos theta+5)/(2tan theta+3 sec theta+5 cos theta +7sin theta+8)= (a) tan (theta/2) (b) cot (theta/2) (c) sec (theta/2) (d) cosec (theta/2)

 (2sec theta + 3 tan theta + 5 sin theta -7cos theta + 5) / (2tan theta + 3 sec theta + 5 cos theta + 7sin theta + 8) = (a) tan (theta / 2)  c  (ceta (theta / 2)                                (c) sec (theta / 2)         (d)     cosec (theta / 2)      Â

Prove that (sec theta+tan theta -1)/(tan theta -sec theta +1)=cos theta/(1-sin theta)

cos theta(tan theta+2)(2tan theta+1)=2sec theta+5sin theta

cos theta(tan theta+2)(2tan theta+1)=2sec theta+5sin theta

cos theta(tan theta+2)(2tan theta+1)=2sec theta+5sin theta

(sin theta+sin3 theta+sin5 theta)/(cos theta+cos3 theta+cos5 theta)=tan3 theta

Prove that (sec theta+tan theta-1)/(tan theta-sec theta+1)=(cos theta)/(1-sin theta)

Prove that: (sec theta + tan theta -1)/(tan theta - sec theta +1) = (cos theta)/(1- sin theta)