pi R^(0)2," यदि "y+sin y=cos x," लो "(dy)/(dx)" ज्ञात कीजिए। "

if y+cos y=sin x , (dy)/(dx)=

If sin(x y)+cos(x y)=0 , then (dy)/(dx) is

If sin(x y)+cos(x y)=0 , then (dy)/(dx) is

If sin(x y)+cos(x y)=0 , then (dy)/(dx) is

If sin ^(2) y+cos (xy)=pi ,then (dy)/(dx) =

sin x cos y+(dy)/(dx)cos x sin y=0

If sin^(2)x+2cos y+xy=0 then (dy)/(dx)=

If sin(x+y) = cos(x-y), then the value of cos^2 x is: यदि sin(x+y) = cos(x-y), तो cos^2 x का मान ज्ञात करें :

If y + sin y = cos x, then (dy)/(dx) at   ((pi)/(2), (pi)/(2)) is :