Home
Class 10
CHEMISTRY
[" The amount of oxalic acid (mol.wt."63...

[" The amount of oxalic acid (mol.wt."63" ) required "],[" to prepare "500" ml of its "0.10N" slution is "],[[" a) "0.315g," b) "3.150g],[" c) "6.300g," d) "1.575g]]

Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the amount of oxalic acid (eq. wt. 63) required to prepare 500 ml of its 0.10N solution.

The amount of oxalic acid (eq. wt 63) required to preare 500 ml of its 0.10 N solution is

The amount of K_(2) Cr_(2)O_(7) ( eq. wt. 49.04) required to prepare 100 ml of its 0.05N solution is

The weight of oxalic acid crystals, H_(2)C_(2)O_(4)2H_(2)O required to prepare 500 ml of 0.2 N solution is,

The mass of oxalic acid crystals H_(2)C_(2)O_(4).2H_(2)O required to prepare 500 mL of 0.2N solutions is .....

The mass of oxalic acid crystals (H_(2)C_(2)O_(4).2H_(2)O) required to prepare 50 mL of a 0.2 N solution is:

The mass of oxalic acid crystals (H_(2)C_(2)O_(4).2H_(2)O) required to prepare 50 mL of a 0.2 N solution is:

The weight of oxalic acid that will be required to prepare a 1000 ml (N/20) solution is -