The equation to the locus of a point P for which the distance from P to (0,5) is double the distance from P to y -axis is
1) `3x^(2)+y^(2)+10y-25=0`
2) `3x^(2)-y^(2)+10y+25=0`
3) `3x^(2)-y^(2)+10y-25=0`
4) `3x^(2)+y^(2)-10y-25=0`

The locus of a point P ,so that the join of (-5,-1) and (3,2) subtend,a right angle at P is x^(2)+y^(2)+2x-3y-13=0 x^2+y^(2)+2x-3y-17=0 x^(2)+y^(2)+2x-y-17=0 x^(2)+y^(2)+4x-2y+1=0

If the distance from P to the points (5,-4),(7,6) are in the ratio 2:3 ,then the locus of P is 5x^(2)+5y^(2)-12x-86y+17=0 , 5x^(2)+5y^(2)-34x+120y+29=0, 5x^(2)+5y^(2)-5x+y+14=0 3x^(2)+3y^(2)-20x+38y+87=0

The locus of a point "P" ,if the join of the points (2,3) and (-1,5) subtends right angle at "P" is x^(2)+y^(2)-x-8y+13=0 x^(2)-y^(2)-x+8y+3=0 x^(2)+y^(2)-4x-4y=0,(x,y)!=(0,4)&(4,0) x^(2)+y^(2)-x-8y+13=0,(x,y)!=(2,3)&(-1,5)

The equation of a circle with radius 5 and touching both the coordinate axes is x^(2)+y^(2)+-10x+-10y+5=0x^(2)+y^(2)+-10x+-10y=0x^(2)+y^(2)+-10x+-10y+25=0x^(2)+y^(2)+-10x+-10y+51=0

Find the distance between the centres of the circles x^(2)-y^(2)+8x+10y-2=0andx^(2)-y^(2)+2x+2y-1=0 .

The equation of the circle of radius 5 in the first quadrant which touches the x-axis and the line 3x-4y=0 is x^(2)+y^(2)-24x-y-25=0x^(2)+y^(2)-30x-10y+225=0x^(2)+y^(2)-16x-18y-64=0x^(2)+y^(2)-20x-12y+144=0

Let P Q R be a right-angled isosceles triangle, right angled at P(2,1)dot If the equation of the line Q R is 2x+y=3 , then the equation representing the pair of lines P Q and P R is (a) 3x^2-3y^2+8x y+20 x+10 y+25=0 (b) 3x^2-3y^2+8x y-20 x-10 y+25=0 (c) 3x^2-3y^2+8x y+10 x+15 y+20=0 (d) 3x^2-3y^2-8x y-15 y-20=0

I. 3x^(2) - 17x+10 = 0 II. 2y^(2) -5y+3 = 0

If the lines 2x+3y+1=0 and 3x-y-4=0 lie along diameters of a circle of circumference 10 pi ,then the equation of the circle is (A) x^(2)+y^(2)-2x+2y-23=0 (B) x^(2)+y^(2)+2x-2y-23=0 (C) x^(2)+y^(2)+2x+2y-23=0 (D) x^(2)+y^(2)-2x-2y-23=0