A particle is projected vertically upwards with velocity `40m//s.` Find the displacement and distance travelled by the particle in
(a) `2s` (b) `4s` (c) `6s` Take `g=10 m//s^2`

A particle is projected vertically upwards with an initial velocity of 40 m//s. Find the displacement and distance covered by the particle in 6 s. Take g= 10 m//s^2.

A particle is projected vertically upwards from ground with velocity 10 m // s. Find the time taken by it to reach at the highest point ?

A ball is projected vertically up wards with a velocity of 100 m/s. Find the speed of the ball at half the maximum height. (g=10 m//s^(2))

A particle is projected from ground with velocity 40sqrt(2)m//s at 45^(@) . At time t=2s

A ball is projected vertically up with speed 20 m/s. Take g=10m//s^(2)

A particle is projected from ground with velocity 40(sqrt2) m//s at 45^@ . Find (a) velocity and (b) displacement of the particle after 2 s. (g = 10 m//s^2)

A particle is projected vertically upward and moves freely under gravity.If the distance travelled by the particle in the 4^(th) second of its motion is twice of that in the 5^( th ) second,then the speed of projection is ?[g=10m/ s^(2) ]

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m//s . The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is ("Take" g = 10 m//s^2) .