`(1+sec20^(@))(1+sec40^(@))(1+sec80^(@))=`

sin20^(@)(4+sec20^(@))=

The value of (1+sec20^(@)+cot70^(@))(1-"cosec"20^(@)+tan70^(@)) is equal to

sec^(-1)[sec(-30^(@))] =

The value of sec 40^(@)+sec 80^(@)+sec 160^(@) will be

sqrt(3)cos sec20^(0)-sec20^(@)

Prove that: (1+sec 2theta)(1+sec2^(2)theta)(1+sec2^(3)theta)...... xx )(1+sec2^(n)theta) = tan2^(n)theta* cot theta

Prove that (tan 8 theta)/(tan theta)=(1+ sec 2 theta)(1+ sec 4 theta)(1+ sec 8 theta)

Solve,(sec^(-1))(x)/(a)-(sec^(-1))(x)/(b)=sec^(-1)b-sec^(-1)a

(sec 2A+1 ) sec ^(2) A=