The base of a triangle lies along `x=5` and is of length `1` .The area of triangle is `1`. The locus of vertex is

The base of a triangle lies along x= 1and is of length 1. The area of triangle is 1. The locus of vertex is

Let the base of a triangle lie along the line x=a and be of length a. The area of this triangle is a2, if the vertex lies on the line

Let the base of a triangle lie along the line x = a and be of length 2a. The area of this triangles is a^(2) , if the vertex lies on the line

If the base of a triangle and the ratio of the lengths of the other two unequal sides are given,then the vertex lies on

If the base of a triangle and the ratio of tangent of half of base angles are given,then identify the locus of the opposite vertex.

If two vertices of a triangle are (1,3) and (4,-1) e and the area of triangle is 5 sq.units,then the angle at the third vertex lies in:

The base of an equilateral triangle is along theline given by 3x+4y=9 .If a verter of the triangle is (1,2), then the length of a side of the triangle is

In a triangle ABC,A(1,3) and perpendicular bisector of AB is y=x and orthocentre of triangle ABC is (3,1), then locus of vertex C is

The equation of the base of an equilateral triangle ABC is x+y=2 and the vertex is (2,-1). The area of the triangle ABC is: (sqrt(2))/(6) (b) (sqrt(3))/(6) (c) (sqrt(3))/(8) (d) None of these