From an elevated point two bodies are projected horizontally in opposite direction with velocity "10m/s" each.Time after which their displacements are perpendicular to each other is`g=10m/s^(2)`

Two particles are projected from a tower horizontally in opposite directions with velocities 10 m//s and 20 m//s . Find the time when their velocity vectors are mutually perpendicular. Take g=10m//s^2 .

From a tower of height 40 m , two bodies are simultaneously projected horizontally in opposite direction, with velocities 2 m s^-1 and 8 ms^-1 . respectively. The time taken for the displacement vectors of two bodies to be come perpendicular to each other is.

A body is projected horizontally from the top of a tower of height 10m with a velocity 10m/s .Its velocity after 1 second is

From a tower of height 40 m , two bodies are simultaneously projected horizontally in opposite direction, with velocities 2 m s^-1 and 8 ms^-1 . respectively. The time taken for the velocity vectors of two bodies to become perpendicular to each other is :

From a tower of height 40 m , two bodies are simultaneously projected horizontally in opposite direction, with velocities 2 m s^-1 and 8 ms^-1 . respectively. The horizontal distance between two bodies, when their velocity are perpendicular to each other, is.

Two particles are projected with speeds u_1 and u_2 in mutually opposite directions from top of a tower horizontally. Find the time after which their velocity becomes perpendicular to each other.

Two projectiles are projected horizontally from the same point in opposite directions with speed 5m/s . Find the separation in meter at the instant their velocities become mutually perpendicular (g=10m/ s^(2) ).

A body is projected horizontally from a height of 78.4m with a velocity 10m/s .Its velocity after 3 seconds is ?[g=10m/ s^(2) ]

At a certain height a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of 10ms^(-1) The time interval after the explosion for which the velocity vectors of the two fragments become perpendicular to each other is (g=10ms^(-2))

Two trains, each 50 m long, are travelling in opposite directions with velocities 10 ms^-1 and 15 ms^-1 . The time of their crossing each other is.