Equation of the plane perpendicular to the line `(x+2)/(1)=(y-1)/(2)=(z+1)/(-1)` and passing through (3,0,5) is `ax+by+cz+2=0` then `a+b+c=`

The equation of the plane perpendicular to the line (x-1)/1=(y-2)/(-1)=(z+1)/2 and passing through the point (2,3,1), is

Prove that the equation of a plane perpendicular to the line x-1=2-y=(z+1)/(2) and passing through (2,3,

The equation of the plane perpendicular to the line (x-1)/(1), (y-2)/(-1), (z+1)/(2) and passing through the point (2, 3, 1) . Is

cartesian equation of the line which is perpendicular to the lines (x)/(2)=(y)/(1)=(z)/(3) and (x-3)/(-1)=(y-2)/(3)=(z+5)/(5) and passes through the point (1,2,3)

If equation of the plane through the parallel lines (x+1)/(3)=(y-2)/(2)=(z)/(1) and (x-3)/(3)=(y+4)/(2)=(z-1)/(1) is ax+by-26z+6=0 , then a+b = ___________

Equation of the line passing through (1,1,1) and perpendicular to the plane 2x+3y-z-5=0 is

A straight line passes through the point (2,-1,-1). It is parallel to the plane 4x+y+z+2=0 and is perpendicular to the line (x)/(1)=(y)/(-2)=(z-5)/(1). The equation of the straight line is